【問題】 ACM Q494 WA

[PichuChen 10]

下面是我的程式碼

#include <stdio.h>

int main(int argc, char *argv[])
{
int k=0;
  char flag=0,ic=1;
  while(1){
  k=0;
  ic=fgetc(stdin);
     while(ic != '\n' && ic != EOF){

                         if((ic >= 65 && ic <=90) || (ic  >= 97 && ic <= 122))
                                flag = 1;
                         else if (flag){
                         flag = 0;
                         k++;
                         }
                         ic=fgetc(stdin);
  }
  if (flag){
  flag = 0;
  k++;
  }
  printf("%d\n",k);	
  if (ic == EOF)break;
}
  return 0;
}

我在懷疑是否是fgetc惹的禍

[devilx 10]

基本上呢

這題陷阱很多= =

可惜我看不懂你寫的XD

我都寫C++

[jim2212001 10]

只要判斷有幾個連續或單一存在的英文字母就可以了

怎麼判斷就自己想嚕～

//我也是用C++寫耶XDrz

[電腦狂 10]

Hmmm...

I wrote by C language and I got AC.

I have studied your code.

Although we use same language,our writing way are still different.

So I'm not understood how you wrote clearly.

I'll PM you my code which got AC.

Just for you to reference.

Enjoy it!

P.S. I always use English in Program writing or chatting because of this Web:

http://acm.uva.es/board/index.php

Try to find answer though this large data library.

[blueminor12 10]

基本上呢

這題陷阱很多= =

可惜我看不懂你寫的XD

我都寫C++

他適用c寫的嗎??