陳碧利

水平拋體

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在海邊的山崖頂上,以 100 m/s 的水平速度發射一砲彈,當砲彈掉落海面時,其運動方向與海平面夾角45°,已
知重力加速度g =10 m/ s 2,且不計空氣阻力,求山崖頂的高度約為多少 m?

1.  500  2.  750    3.  1000    4.   1250

答案:1

問題1為何水平初速=水平末速??也為何垂直末速亦為100m/s?

            (跟海平面夾45度有關??)
            

問題2:水平拋體公式的公式是甚麼?
問題3:下圖中V=Vo+gt(為何Vo=0????)
 

 

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